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saw5 [17]
3 years ago
13

population 1 is normally distributed with a mean of 40 and a standard deviation of 4, and population 2 is normally distributed w

ith a mean of 25 and a standard deviation of 7.

Mathematics
1 answer:
Softa [21]3 years ago
8 0

Answer:

It must be A i mean i worked it out for a few so thats what i came up with

Step-by-step explanation:

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W-x+y;w=6,×=5,y=3 math problem
cricket20 [7]
6-5 = 1, 1 + 3 = 4 
Answer is 4
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3 years ago
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Which of these is the algebraic expression for "4 times the sum of 2 and y?"
solmaris [256]

Answer:

b

Step-by-step explanation:

The sum of 2 and y is 2 + y, then 4 times this sum is

4(2 + y) → b

4 0
3 years ago
Issouf claims that the scale factor is 1/2. which statement about his claim is correct?
love history [14]

Answer:

The correct option is D.

Step-by-step explanation:

It is given that Issouf claims that the scale factor is 1/2.

From the given figure it is clear that

CB'=C'B'=2

B'B=6

CB=CB'+B'B=2+4=6

The scale factor of a figure is

k=\frac{\text{Length of any side of image}}{\text{Length of corresponding side of preimage}}

k=\frac{C'B'}{CB}

k=\frac{2}{6}

k=\frac{1}{3}

The scale factor is 1/3 because CB is actually 2 + 4 = 6.

Therefore the correct option is D.

4 0
3 years ago
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WILL MARK BRANLIEST A graph is shown below: Dotted line joining negative 1, negative 2 and 5,0 and the region above the line is
s2008m [1.1K]
Hello there!

<span>A graph is shown below: Dotted line joining negative 1, negative 2 and 5,0 and the region above the line is shaded. Which of the following inequalities is best represented by this graph? x − 3y > 5 x − 3y < 5 x − 2y > 5 x − 2y < 5

Answer: 
</span><span>x – 3y < 5</span>
4 0
3 years ago
Why did I get this question wrong?
Vlad1618 [11]

You set up was almost accurate. Remember the arc length formula:

If f'(y) is continuous on the interval [a,b], then the length of the curve x = f(y), a ≤ y ≤ b should be;

L = ∫ᵇ ₐ √1 + [f'(y)]^2 * dy

We have to find the length of the curve given x = √y - 2y, and 1 ≤ y ≤ 4. You can tell your limits would be 1 to 4, and you are right on that part. But f'(y) would be rather...

f'(y) = 1/(2√y) - 2

So the integral would be:

∫⁴₁ √1 + (1/(2√y) - 2)² dy

Using a calculator we would receive the solution 5.832. Their is a definite curve, as represented below;

8 0
3 years ago
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