Okay so you have to add up 15 and 11 and 4 so your answer is y=30
Answer:
C
Step-by-step explanation:
trust
Answer:
0.1587
Step-by-step explanation:
Here, mean=μ=100 and standard deviation=σ=16.
We have to find P(average MDI scores of 64 children > 102)=P(xbar>102).
n=64
μxbar=μ=100
σxbar=σ/√n=16/√64=16/8=2
P(xbar>102)=P((xbar-μxbar)/σxbar>(102-100)/2)
P(xbar>102)=P(z>1)
P(xbar>102)=P(0<z<∞)-P(0<z<1)
P(xbar>102)=0.5-0.3413
P(xbar>102)=0.1587
Thus, the probability that the average is greater than 102 is 15.87%
X=3 pretty sure
Hope this helps!!
