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Anuta_ua [19.1K]
2 years ago
14

1) Last Tuesday, Regal Cinemas sold a total of 85 movie tickets. Ticket sales totaled

Mathematics
1 answer:
irakobra [83]2 years ago
7 0

In this question, some of the data is missing so its a complete question and the solution can be defined as follows:

\bold{\text{m = matinee tickets}} \\\\\bold{\text{s = student tickets}}\\\\\bold{\text{r = regular tickets}}

By given question, calculating equations are:

\to \bold{m + s + r = 8500}............................................(a)\\\\\to \bold{5m + 6s + 8.50r = 64600}............................(b)\\\\\to \bold{s = 2m}...................(c)

Putting the equation (c) value in the equation (a) to calculate value:

m + 2m + r = 8500\\\\3m + r = 8500\\\\r = 8500 - 3m........................................(d)

Putting equation (c) and (d) value into equation (b):

5m + 6(2m) + 8.50(8500 - 3m) = 64600\\\\5m + 12m + 72250 - 25.50m = 64600\\\\-8.50m = 64600 - 72250 \\\\-8.50m = -7650\\\\m = \frac{-7650}{-8.50}\\\\m = \frac{7650}{8.50}\\\\m = 900

Putting m value into equation (c) and equation (d) to calculate its value:

Calculating the s value:

\to s = 2(900) \\\\ \to s = 1800

Calculating the r value:

\to r = 8500 - 3(900) \\\\\to r = 8500 - 2700\\\\\to r = 5800\\\\

So, the final value of "m, s, and r" are "900, 1800, and 5800".

Learn more:

brainly.com/question/2929577

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Name another ordered pair that is on the graph
kotegsom [21]

Answer:

(5,30)

Step-by-step explanation:

That is the constant change in the y's as the x's increase by 1?

12 - 6 = 6

18 - 12 = 6

24 - 18 = 6

The common difference is 6 so the next coordinate will be 6 more on the y and 1 more on the x.

(5,30)

4 0
2 years ago
Bill has a box of markers that has a base of 8 cm by 20 cm and a height of 6 cm. Martin's pencil box has a height of 4 cm and a
Maslowich
Ok so you need to multiply the length, width, and height together for each one.
Bill: 8 x 20 x 6 = 960
Martin: 4 x 15 x 16 = 960
So Bill is right, they both have the same volume.
8 0
2 years ago
Read 2 more answers
Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0
3 years ago
PLEASE HELP!!! 25 POINTS!!!
Phoenix [80]
6 4
5

2 3
6

7 5
3

2 4
8

3 5
7
3 0
2 years ago
Find a polynomial f(x) of degree 4 that has the following zeros. 2, 5, 0, -7
Otrada [13]

Answer:

Step-by-step explanation:

f(x) = (x - 2)(x - 5)x(x+ 7)

f(x) = (x^2 - 7x + 10)*x * (x + 7)

f(x) = x(x^3 - 39x + 70)

f(x) = x^4 - 39x^2 + 70x

To show that this is correct, I've made a graph with these points labeled. The graph is just around the x axis. The local maximums and minimums are just too large a value.

6 0
2 years ago
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