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oksian1 [2.3K]
3 years ago
5

How many more ways can 10 juniors running for the positions of president, vice president, secretary, treasurer be selected when

compared to 12 sophomores running for 5 identical positions of class representative's?
Mathematics
1 answer:
zubka84 [21]3 years ago
5 0
10 juniors are running for 4 positions. 
There are ten people who can get into the first spot
Nine people for the second
8 people for the third
7 for the fourth
10x9x8x7= 5040 different ways. 

For the sophomores: 12x11x10x9x8= 95040
However, the positions are identical which means that the order doesn't matter. (There's a difference between A getting postion 1, B for 2, C for 3, D for 4 and B for 1, A for 2, C for 3, D for 4)

There are 5 identical positions, therefore we divide this by 5! (5x4x3x2x1)= 120
95040/120= 792
Juniors have 5040 positions, sophomores have 792





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