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2 years ago

Find the smallest integer value of X that satisfies the inequality of 6X>7

Mathematics

1 answer:

Nastasia [14]2 years ago

5 0

Answer:

x = 2

Step-by-step explanation:

The solution set can be found by dividing the inequality by the coefficient of x.

6x > 7

x > 7/6

The smallest integer greater than 7/6 is 12/6 = 2.

The smallest integer solution is x = 2.

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Marat540 [252]

Lxwxh using your numbers its 3x3x3 or 3³ so your answer is 27

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2 years ago

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Someone help me please with this algebra problem

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

3r = 10 + 5s

r = 10

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2 years ago

What goes where. JdhshshHshxjancixd

valentina_108 [34]

Answer:

$\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }$

$\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }$

Step-by-step explanation:

We need to simplify

$y + \frac{2}{5}y$

We collect LCM to get;

$\frac{5y + 2y}{5} = \frac{7y}{5}$

Therefore:

$\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }$

Also we need to simplify:

$y - \frac{2}{5}y$

We collect LCM to get;

$y - \frac{2}{5}y = \frac{5y - 2y}{5} = \frac{3}{5} y$

Therefore

$\boxed { \frac{3}{5}y } \to \: \boxed {y - \frac{2}{5}y }$

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3 years ago

Factorise the following: a) x + 3x - 4 b) x - 2x - 3 c) x + 2x - 8

Komok [63]

Are they supposed to be quadratic equations? Is it x^2 +3x -4 etc?

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2 years ago

Jay, Kay, and Ray found themselves far apart when they stopped for lunch while walking in a field. Jay could see Kay, then turn

MariettaO [177]

Hi There! :)

Jay, Kay, and Ray found themselves far apart when they stopped for lunch while walking in a field. Jay could see Kay, then turn through 75th, and couldsee Ray. Jay could see Ray, then turn through 50th amd see Jay. Ray could see Jay, the turn through 55th, and see Kay. Which two were the farthest apart?

A. Kay and Ray
B. Jay and Kay
C. Ray and Jay
D. Kay and Ray were the same distance apart as Ray and Jay

I believe it's A. Kay and Ray

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2 years ago

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