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2 years ago

Find the smallest integer value of X that satisfies the inequality of 6X>7

Mathematics

1 answer:

Nastasia [14]2 years ago

5 0

Answer:

x = 2

Step-by-step explanation:

The solution set can be found by dividing the inequality by the coefficient of x.

6x > 7

x > 7/6

The smallest integer greater than 7/6 is 12/6 = 2.

The smallest integer solution is x = 2.

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Your best friend is really struggling with their math class. You passed the same class last term with an A, so you’ve been helpi

ra1l [238]

Answer:

Step-by-step explanation:

you have done your part by helping in their study session,if you help them cheat you will suffer the consequences if he/she is caught,

3 0

2 years ago

Short Response

garik1379 [7]

Answer:

(a)2(89x+84)

(b) $2(89x+84-x^2\pi)$

Step-by-step explanation:

The dimensions of the larger rectangular field are:

Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain = $\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi$

Area of the Field that does not include the soccer field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

$=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)$

8 0

4 years ago

The smiths previously lived in a house that had 1450 sq ft of space. The sq ft of their new home is 3800 sq ft. What is the perc

lana66690 [7]

Answer:

162.1%

Step-by-step explanation:

Given that:

Size of previous living space = 1450 sq ft

Size of new living space = 3800 sq ft

% increase in living space ;

Increase in living space = 3800 - 1450 = 2350 sq feet

(Increase / previous size) * 100%

(2350 / 1450) * 100%

1.6206 * 100%

= 162.06%

= 162.1%

5 0

3 years ago

If a baseball team's ratio of wins to losses is 5 to 4, what is the ratio of wins to total games played?

lara [203]

I believe it's 5 to 9 since out of 9 games they win 5 and lose 4. This doesn't account for draws or anything, though.

8 0

3 years ago

A report by the US Geological Survey indicates that glaciers in Glacier National Park, Montana, are shrinking. Recent estimates

postnew [5]

Answer

a) C

b) B

c) C, E

d) 15.5

e) 0.7

f) 67.7

Step-by-step explanation

a) A linear equation can be written as $y=mx+c$ where $m$ is the slope and $c$ is the intercept on the $y$ -axis. The slope describes how $y$ changes when $x$ changes. A negative value means the it is a decreasing change. In our case, $y$ is $A$ and $x$ is $t$ . Thus, the slope of the equation is $m=-0.062$ . This means that the area of glacier is decreasing by $0.062 \text{km}{}^2 = 62000 \text{m}{}^2$ every year since 2000.

b) The $A$ -intercept (= 16.2 $\text{km}{}^2$ ) represents the area covered when $t=0$ . But $t=0$ starting from year 2000. This intercept then represents the area covered by glacier in the year 2000. Therefore, the area covered by glacier in 2000 was 16.2 $\text{km}{}^2$ .

c) $A=f(t)$ means the area covered after year 2000. Setting it to 12 means the area covered after $t$ years is 12 $\text{km}{}^2$ ). $t$ is therefore the number of years since 2000 that the total area covered will be 12 $\text{km}{}^2$ ).

d) $f(12)=16.2−0.062\times12 =16.2-0.744 = =15.456 15.5 \text{km}{}^2$ to 1 decimal place.

e) The term involving $t$ represents the disappearing area. In 12 years, the disappeared area is $0.062\times12=0.744 =0.7 \text{km}{}^2$ to 1 decimal place.

f) $f(t)=16.2−0.062t =12$

$0.062t = 16.2-12 = 4.2$

$t = \dfrac{4.2}{0.062}=67.7419\ldots =67.7$ years to 1 decimal place.

8 0

3 years ago