Answer:
J'(2,-3), K'(4, -3) and L'(5,-2)
Step-by-step explanation:
The given triangle has vertices at J(2,3), K(4, 3) and L(5,2).
The transformation rule for a reflection in the x-axis is:
We substitute the points to obtain the coordinates of the image triangle J'K'L'
In other words, we negate the y-coordinates of triangle JKL to obtain the coordinates of J'K'L'
See attachment for graph.
The statements that are true about the intervals of the continuous function are Options 2, 4 and 5
Looking at the values given, the intervals which satisfies the condition are known to be:
f(x)<=0 over the interval [0,2]
f(x)>0 over the interval (-2,0)
f(x)>=0 over the interval [2,∞)
Because:
Since the table with x and f(x) values, we have to examine analyze the table and see the each option that is in line with f(x) or not .
Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)
Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]
When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)
When you look at the interval (-2,0) , the f(x) is positive and as such, f(x)>0 over the interval (-2,0)
Looking at the interval [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)
Therefore, Option 2, 4 and 5 are correct.
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