How to solve (4s+5t)(4s-5t)
1 answer:
You might be interested in
Answer:
<u>Given expression:</u>
<u>The first root is valid when:</u>
- 2x + 2 ≥ 0 ⇒ 2x ≥ - 2 ⇒ x ≥ - 1
<u>The second root is valid when:</u>
- 6 - 4x ≥ 0 ⇒ 4x ≤ 6 ⇒ x ≤ 1.5
<u>So the variable x can get values within interval:</u>
- -1 ≤ x ≤ 1.5 or
- x = [-1, 1.5]