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zavuch27 [327]
3 years ago
8

What is the value of x? Four-fifths x minus StartFraction 1 Over 10 Endfraction = StartFraction 3 Over 10 EndFraction One-fourth

StartFraction 8 Over 25 EndFraction Two-fifths One-half
Mathematics
2 answers:
DerKrebs [107]3 years ago
9 0

Answer:

Its 1/2 :)

Step-by-step explanation:

Sedbober [7]3 years ago
8 0

Answer:

<h3>1/2</h3>

Step-by-step explanation:

Given the expression

4/5 x - 1/10 = 3/10

We are to find the value of x

4/5 x = 3/10 + 1/10

4/5 x = 4/10

Cross multiply

4x * 10 = 5 * 4

40x = 20

x = 20/40

x = 1/2

The value of x is 1/2

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A jacket usually sells for $66.00. If the jacket is 30% off, and sales tax is 8%, what is the total price of the jacket, includi
RideAnS [48]

Answer:

$50.54

Step-by-step explanation:

$66.00 x .30 = $46.80 x .08 = 3.74 + 46.80 = $50.54

7 0
3 years ago
Solve Ix - 11 &gt; 4
yanalaym [24]

Answer:

A.

Step-by-step explanation:

6 0
3 years ago
When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F
aleksandr82 [10.1K]

Let x be the unknown number. So, three times that number means 3x, and the square of the number is x^2

We have to sum 528 and three times the number, so we have 528+3x

Then, we have to subtract this number from x^2, so we have

x^2-(3x+528)

The result is 120, so the equation is

x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0

This is a quadratic equation, i.e. an equation like ax^2+bx+c=0. These equation can be solved - assuming they have a solution - with the following formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

If you plug the values from your equation, you have

x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}

So, the two solutions would be

x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27

x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24

But we know that x is positive, so we only accept the solution x = 27

6 0
3 years ago
{(-9,3) (5,-6) (3,-1), (-6,5), ?}Which ordered pair can replace the missing value and make the set if ordered pairs NOT a functi
Nookie1986 [14]
\text{Slope}=\frac{-1--6}{3-5}=\frac{5}{-2}\begin{gathered} y-y_1=\frac{5}{-2}(x-x_1) \\  \\ y--6=\frac{5}{-2}(x-5) \\  \\ -2(y+6)=5(x-5) \\ -2y-12=5x-25 \\ 5x+2y=25-12 \\ 5x+2y=13 \end{gathered}

The missing values are (-6, -9) ( The last option)

Explanation:

x= - 6 has already produced the value of y as 5, the only pair in the given option the make the given ordered pairs NOT to be a function is (-6, -9) since it will give the value of y to be - 9.

4 0
1 year ago
Need help on this! thanks :)
dedylja [7]

Answer:

1/3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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