Plz help me i need to ace this tyvm =3

Mathematics

1 answer:

Irina-Kira [14]3 years ago

5 0

First looks more bell than anything, second, there are 18-time trials, third, I'm not completely sure.

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Urgent ;<br>if a^3+b^3=11 and a^3-b^3=5, evaluate a^6-b^6

11111nata11111 [884]

Factorize using the difference of squares identity.

$a^6 - b^6 = \left(a^3\right)^2 - \left(b^3\right)^2 = \left(a^3 - b^3\right) \left(a^3 + b^3\right)$

Then

$a^6 - b^6 = 11 \cdot 5 = \boxed{55}$

5 0

1 year ago

Assume that adults have IQ scores that are normally distributed with a mean of 96 and a standard deviation of 15.7. Find the pro

astraxan [27]

Answer:

4.05% probability that a randomly selected adult has an IQ greater than 123.4.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 96, \sigma = 15.7$