9514 1404 393
Answer:
a) average rate = (total distance)/(total time)
b) Rave = 2·R1·R2/(R1 +R2)
c) cheetah's average rate ≈ 50.91 mph
Step-by-step explanation:
a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...
First leg distance: AB = 70·t1 ⇒ t1 = AB/70
Second leg distance: AB = 40·t2 ⇒ t2 = AB/40
The average rate is the ratio of total distance to total time:
average rate = (AB +AB)/(t1 +t2)
average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)
average rate = 560/11 = 50 10/11 . . . mph
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No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.
b) For two rates over the same distance (as above), the average is their harmonic mean:
average rate = 2r1·r2/(r1+r2)
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c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.
Answer:
3
Step-by-step explanation:
i think because 12-9=3
Solve for x:
1.
4x - 7 = 3
Add 7 to both sides
4x = 10
Divide both sides by 4
x = 10/4
Simplify:
x = 5/2
Answer for question 1: x = 5/2
2.
13 + 2x/3 = 15
Multiply both sides by 3
39 + 2x = 45
Subtract 39 from both sides
2x = 6
Divide both sides by 2
x = 3
Answer for question 2: x = 3
3.
10x + 7 = 15
Subtract 7 from both sides
10x = 8
Divide both sides by 10
x = 8/10
Simplify
x = 4/5
Answer for question 3: x = 4/5
1.
2.
<u> </u><u>Sub (1, -5) into equation to find '</u><em><u>b'</u></em><u />
3.
4.
Answer:
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