Answer:Option C:
64 \ cm^2 is the area of the composite figure
It is given that the composite figure is divided into two congruent trapezoids.
The measurements of both the trapezoids are
b_1=10 \ cm
b_2=6 \ cm and
h=4 \ cm
Area of the trapezoid = \frac{1}{2} (b_1+b_2)h
Substituting the values, we get,
A=\frac{1}{2} (10+6)4
A=\frac{1}{2} (16)4
A=32 \ cm^2
Thus, the area of one trapezoid is $32 \ {cm}^{2}$
The area of the composite figure can be determined by adding the area of the two trapezoids.
Thus, we have,
Area of the composite figure = Area of the trapezoid + Area of the trapezoid.
Area of the composite figure = $32 \ {cm}^{2}+32 \ {cm}^{2}$ = 64 \ cm^2
Thus, the area of the composite figure is 64 \ cm^2
Step-by-step explanation: