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Svetradugi [14.3K]
3 years ago
12

D. One holding pen uses 500 feet of fence

Mathematics
1 answer:
denis23 [38]3 years ago
3 0
The answer is a I think
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Determine the largest integer value of a for which f(x)= ax^2+9x+5 has 2 distinct, real zeros (please show work)
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4 years ago
If the solution to y=4x+3 is (4,16) what would the steps needed to get (4,16) be?
Ainat [17]
<span>Simplifying x4 = 16
 Solving x4 = 16
 Solving for variable 'x'.
  Move all terms containing x to the left, all other terms to the right.
Simplifying x4 = 16
 Reorder the terms: -16 + x4 = 16 + -16
 Combine like terms: 16 + -16 = 0 -16 + x4 = 0
 Factor a difference between two squares. (4 + x2)(-4 + x2) = 0
 Factor a difference between two squares. (4 + x2)((2 + x)(-2 + x)) = 0
Subproblem 1

Set the factor '(4 + x2)' equal to zero and attempt to solve:
 Simplifying 4 + x2 = 0 Solving 4 + x2 = 0
 Move all terms containing x to the left, all other terms to the right.
 Add '-4' to each side of the equation. 4 + -4 + x2 = 0 + -4
 Combine like terms: 4 + -4 = 0 0 + x2 = 0 + -4 x2 = 0 + -4
 Combine like terms: 0 + -4 = -4 x2 = -4
 Simplifying x2 = -4
The solution to this equation could not be determined.
 This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + x)' equal to zero and attempt to solve:
 Simplifying 2 + x = 0 Solving 2 + x = 0
 Move all terms containing x to the left, all other terms to the right.
 Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2
 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Sub-problem 3

Set the factor '(-2 + x)' equal to zero and attempt to solve:
 Simplifying -2 + x = 0 Solving -2 + x = 0
 Move all terms containing x to the left, all other terms to the right.
 Add '2' to each side of the equation. -2 + 2 + x = 0 + 2
 Combine like terms: -2 + 2 = 0 0 + x = 0 + 2 x = 0 + 2
 Combine like terms: 0 + 2 = 2 x = 2 Simplifying x = 2Solutionx = {-2, 2}</span>
8 0
3 years ago
What is the instantaneous rate of change of f(x)=xe^x-(x 2)e^(x-1) at x=0 ?
lozanna [386]
You have to derive for a multiplication in both terms:
=e^x+xe^x-(e^x-1 + (x-2)e^x-1) now apply distributive property in the last term:
=e^x+xe^x+e^x-1-xe^x-1   now replace each x by 0 (x=0)
=1 + 0 + e^-1 + 0 = 1+ e^-1 = 1.3679
8 0
3 years ago
In which months were the expenses greater than the income? Name the month and find how much money was lost.
Liono4ka [1.6K]
 expenses is greater in Jan and Feb

Jan −85.6 Loss
   
Feb −162.44 Loss    

Mar 0 

June 306.77 Gain

July 301.5 Gain

Aug 337.88 Gain


5 0
3 years ago
Read 2 more answers
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