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Naily [24]
3 years ago
5

Anyone knowww thiusss ? no scammers pleaseeee

Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:

about 9cm

Step-by-step explanation:

Muliply the radius by itself: 16x16

Mulitply the answer by 3.14.

Divide 7252 by the answer to get 9

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podryga [215]

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3 0
3 years ago
The circumference of the equator of a sphere was measured to be 82 82 cm with a possible error of 0.5 0.5 cm. Use linear approxi
True [87]

Answer:

The maximum error in the calculated surface area is approximately 8.3083 square centimeters.

Step-by-step explanation:

The circumference (s), in centimeters, and the surface area (A_{s}), in square centimeters, of a sphere are represented by following formulas:

A_{s} = 4\pi\cdot r^{2} (1)

s = 2\pi\cdot r (2)

Where r is the radius of the sphere, in centimeters.

By applying (2) in (1), we derive this expression:

A_{s} = 4\pi\cdot \left(\frac{s}{2\pi} \right)^{2}

A_{s} = \frac{s^{2}}{\pi^{2}} (3)

By definition of Total Differential, which is equivalent to definition of Linear Approximation in this case, we determine an expression for the maximum error in the calculated surface area (\Delta A_{s}), in square centimeters:

\Delta A_{s} = \frac{\partial A_{s}}{\partial s} \cdot \Delta s

\Delta A_{s} = \frac{2\cdot s\cdot \Delta s}{\pi^{2}} (4)

Where:

s - Measure circumference, in centimeters.

\Delta s - Possible error in circumference, in centimeters.

If we know that s = 82\,cm and \Delta s = 0.5\,cm, then the maximum error is:

\Delta A_{s} \approx 8.3083\,cm^{2}

The maximum error in the calculated surface area is approximately 8.3083 square centimeters.

6 0
3 years ago
Suppose that the water level of a river is 34 feet and that it is receding at a rate of 0.5 foot per day. Write an equation for
vivado [14]

Answer:

The equation to represent the rate of receding water level is                     L = 34 (0.5)^{d}   .

Step-by-step explanation:

Given as :

The initial level of water in river = 34 feet

The rate of receding water level = 0.5 foot per day

Or, The rate of percentage of receding water level = 50 % per day

Let the level of water after d days = L

Now,

The level of water after d days = initial level of water × ( (1-\dfrac{\textrm Rate}{100})^{Time}

I.e L = 34 × ( (1-\dfrac{\textrm 50}{100})^{d}

∴  L = 34 × (0.5)^{d}

Hence The equation to represent the rate of receding water level is                L = 34 (0.5)^{d}   . Answer

5 0
3 years ago
Please I need the answer :-)​
Arturiano [62]

Answer:

Step-by-step explanation:

5 0
2 years ago
Solve for y x=y^2+4y
Lorico [155]
x=y^2+4y\\ y^2+4y-x=0\\\Delta=4^2-4\cdot1\cdot(-x)=16+4x\\\\
1.\ \Delta0\\
\sqrt{\Delta}=\sqrt{16+4x}=\sqrt{4(4+x)}=2\sqrt{x+4}\\
y_1=\frac{-4-2\sqrt{x+4}}{2\cdot1}=-2-\sqrt{x+4}\\
y_2=\frac{-4+2\sqrt{x+4}}{2\cdot1}=-2+\sqrt{x+4}\\

-----------------------------------------------------

x=y^2+4y\\ y^2+4y-x=0\\
y^2+4y+4-4-x=0\\
(y+2)^2=x+4\\
y+2=\sqrt{x+4} \vee y+2=-\sqrt{x+4}\\
y=-2+\sqrt{x+4} \vee y=-2-\sqrt{x+4}\\

4 0
4 years ago
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