y= -3/1x + 5
i believe you just miscounted
If she went back 5 miles than the displacement would be 0.
Just subtract the amount of miles she went back from the miles she went forward 5 - 5 = 0
The answer you're looking for my good lad is C
Answer:
No, he not correct because he only ran 4 mi
Step-by-step explanation:
If he walks for 6 min out of the 38 min, then he ran for 32 min.
d = rt 1 mi = 8r
r = 1/8 = 1 mi/8 min Since he ran 32 min we have
d = 1/8(32) = 4 mi.
No, he not correct because he only ran 4 mi
Answer:
Step-by-step explanation: