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3 years ago

What is the unit ratio for a button of 16 grams and 2 milliliters?

Mathematics

1 answer:

Reika [66]3 years ago

6 0

Answer:

The unit ratio would be 8 grams per milliliters

Step-by-step explanation:

Since, the unit ratio is a fraction with denominator 1,

In other words, the amount of one quantity in unit amount of other quantity is called unit rate or unit ratio.

Here, the amount first quantity = 16 grams,

The amount of second quantity = 2 milliliters,

Thus, unit ratio = $\frac{\text{First quantity}}{\text{Second quantity }}$

$=\frac{16}{2}$ = 8 grams per milliliters

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3 years ago

What are the x and y-intercepts of the line described by the equation?

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Answer:

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3 years ago

Make x the subject of the formula y= 2x +5

Kryger [21]

Answer:

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2 years ago

Mathematically verify the outlier(s) in the data set using the 1.5 rule.

statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

$Q_1=\dfrac{11+13}{2}$

$Q_1=\dfrac{24}{2}$

$Q_1=12$

And

$Q_3=\dfrac{16+16}{2}$

$Q_3=\dfrac{32}{2}$

$Q_3=16$

The interquartile range is:

$IQR=Q_3-Q_1$

$IQR=16-12$

$IQR=4$

The data values lies outside the interval $[Q_1-1.5IQR,Q_3+1.5IQR]$ are known as outliers.

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]$

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

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3 years ago