Answer:
So a point is (-3,-5) and the vertex is (-4,-3)
Step-by-step explanation:
This is in vertex form. Vertex form is y=a(x-h)^2+k where (h,k) is the vertex.
The vertex here is (-4,-3)... now just use a value of x to plug in (any value besides -4)
I will choice -3. This gives -2(-3+4)^2-3
f(-3)=-2(1)^2-3
f(-3)=-2-3
f(-3)=-5
So a point is (-3,-5) and the vertex is (-4,-3)
Answer:
y = -2
Step-by-step explanation:
The y-intercept is the y-coordinate of the point where the curve intersects (crosses) the y-axis, i.e. when x = 0.
Therefore, to find the y-intercept, substitute x = 0 into the function:
![f(0)=\sqrt[3]{0+1} -3=\sqrt[3]{1} -3=1-3=-2](https://tex.z-dn.net/?f=f%280%29%3D%5Csqrt%5B3%5D%7B0%2B1%7D%20-3%3D%5Csqrt%5B3%5D%7B1%7D%20-3%3D1-3%3D-2)
Therefore, the curve crosses the y-axis at (0, -2) and so the y-intercept is
y = -2.
Answer:

Step-by-step explanation:
Given expression:

Let u = (x - y):

To factor a quadratic in the form
find two numbers that multiply to
and sum to
:


Therefore, the numbers are: -6 and -4.
Rewrite
as the sum of these two numbers:

Factor the first two terms and the last two terms separately:

Factor out the common term (u - 2):

Substitute back in u = (x - y):

Simplify:

Answer: 76
Step-by-step explanation:
The angles are congruent on both sides