Your rise over run will be -3 over 1 your going to start at the point 5 on the y-axis when your at the point 5 go down 3 then over to the right 1 keep going till it off the graph. Now do the opposite way and go up 3 from 5 and to the left 1 and keep doing that till it’s off the graph.
Hope this helps
First, we have to figure out how much cheese we have total. Do this by adding up all of the various cheeses.
Now to split the cheeses into sections of 1/4 pound each, we have to divide by 1/4, which is the same as multipling by 4
13 slices total
Where is the question dude?
<span>You are given the waiting times between a subway departure schedule and the arrival of a passenger that are uniformly distributed between 0 and 6 minutes. You are asked to find the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes.
Le us denote P as the probability that the randomly selected passenger has a waiting time greater than 3.25 minutes.
P = (length of the shaded region) x (height of the shaded region)
P = (6 - 3.25) * (0.167)
P = 2.75 * 0.167
P = 0.40915
P = 0.41</span><span />
S and P are mutually exclusive events.
P ( S ) = 20% = 0.20
P ( T ) = 22 % = 0.22
The probability of mutually exclusive events:
P ( S or T ) = P ( S ) + P ( T )
P ( S or T ) = 0.20 +0.22 = 0.42
Answer: The probability of ( S or T ) is 0.42 or 42 %.
