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gregori [183]
3 years ago
12

The sum of the digits of a 2-digit number is 10. If 18 is added to the number, the digits of the new number are those of the ori

ginal number but in reverse order. Find the original number.
Mathematics
1 answer:
Aliun [14]3 years ago
7 0

Answer:

46

Step-by-step explanation:

Let (ab) represent a number with a in the ten's position and b is the one's position.

This means (ab) actually has value of 10a+b.

We are given the sum of those digits of (ab) is 10; this means a+b=10.

It says if 18 is added to the number (ab), then the result is (ba).

So (ab) has value 10a+b and

(ba) has value 10b+a.

We are given then:

(ab)+18=(ba)

10a+b+18=10b+a

Subtract 10a on both sides:

b+18=10b+a-10a

Simplify:

b+18=10b-9a

Subtract b on both sides:

18=10b-b-9a

18=9b-9a

Divide both sides by 9:

2=b-a

Rearrange by commutative property:

2=-a+b

So the system of equations we want to solve is:

a+b=10

-a+b=2

-------------------------Add equations together (this will eliminate the variable a and allow you to go ahead and solve for b:

0+2b=12

2b=12

Divide both sides by 2:

b=\frac{12}{2}

Simplify:

b=6

If b=6 and a+b=10, then a=4.  a=4 since 4+6=10.

So the original number is (46).

18 more than 46 is 18+46=(64) which is what we wanted.

We also have the sum of 4 and 6 is 10 as well.

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