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Olegator [25]
3 years ago
12

525 divided by 9 I forgot how to divide

Mathematics
1 answer:
Kryger [21]3 years ago
4 0

Answer:

58.3 repeated

Step-by-step explanation:

hope this helps :)

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Answer this and ill give brainliest
nekit [7.7K]

Answer:

-4.65< -4 and 2/5

Step-by-step explanation:

To solve, this we can convert the fraction -4 and 2/5 into a decimal so that the values can be more easily compared. When we do this, we get the result that -4 and 2/5 equals -4.4. Now we can clearly see which value is greater because they are written in the same form:

-4.65<-4.4

-4.65<-4 2/5

6 0
3 years ago
Read 2 more answers
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morpeh [17]
............ ........... .

7 0
2 years ago
A phone sells for $250. It is now on sale for 1··5off the original price. April has a coupon for an extra 10% off the sale price
anastassius [24]

It's on a sale for 1 fifth of the original price?

4 0
3 years ago
Please answer hurry!!!!
lutik1710 [3]
The best way to solve this problem is by plugging in each answer choice for both equations and seeing which one works. You can already see that choice A doesn't work because -1 is not greater than or equal to 4. That means you just need to test choices B and C!

Choice B (4, -2)
x + y  \geq 6\\&#10;4 + -2  \geq 6\\&#10;2  \geq  6 &#10;
2 is not greater than or equal to 6, so choice B doesn't work.

Choice C (4, 2)
x + y \geq 6\\ &#10;4 + 2 \geq 6\\ &#10;6 \geq 6 \\\\&#10;x  \geq 4\\&#10;4 \geq 4
Since 6 is equal to 6 and 4 is equal to 4, choice C works!

-------

Answer: C) (4, 2)
6 0
3 years ago
A basic cellular phone plan costs $4 per month for 70 calling minutes. Additional time costs $0.10 per minute. The formula C= 4+
Harrizon [31]

Answer:

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

Step-by-step explanation:

The problem states that the monthly cost of a celular plan is modeled by the following function:

C(x) = 4 + 0.10(x-70)

In which C(x) is the monthly cost and x is the number of calling minutes.

How many calling minutes are needed for a monthly cost of at least $7?

This can be solved by the following inequality:

C(x) \geq 7

4 + 0.10(x - 70) \geq 7

4 + 0.10x - 7 \geq 7

0.10x \geq 10

x \geq \frac{10}{0.1}

x \geq 100

For a monthly cost of at least $7, you need to have at least 100 calling minutes.

How many calling minutes are needed for a monthly cost of at most 8:

C(x) \leq 8

4 + 0.10(x - 70) \leq 8

4 + 0.10x - 7 \leq 8

0.10x \leq 11

x \leq \frac{11}{0.1}

x \leq 110

For a monthly cost of at most $8, you need to have at most 110 calling minutes.

For a monthly cost of at least $7 and at most $8, you can have between 100 and 110 calling minutes.

8 0
3 years ago
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