The answer is <span>Anaphase I separates homologous chromosomes and anaphase II separates sister chromatids into daughter cells.</span>
Meiosis is a cell division which results in the reduction of chromosome number by half - from diploid to haploid - in daughter cells. It consists of meiosis I and meiosis II. Meiosis I produces two haploid cells. Meiosis II is analogous to mitosis, so in total, meiosis results in four haploid cells. So, in meiosis, there are two anaphases - the anaphase I in meiosis I and the anaphase II in meiosis II.
<span>In anaphase I, the sister chromatids separate from each other to the opposite sides of the cells. In meiosis I there are 46 chromosomes in duplicate, which are present as pairs of sister chromatids. In anaphase of meiosis II, since the cell is haploid, there are 23 chromosomes in duplicate, which are present as sister chromatids.</span>
I think the answer is the individuals born per unit time.
Well if both are dominate colors the phenotype of the offsprings would be pink or spotted. if the red flowering plant was dominate and the white flowering plant is recessive then the phenotype would be 100% red, they would just be the carrier of the white color. if the white flower is dominate and the red is recessive the flowers phenotype would be 100% white, but be carriers of the red color.
Hunting, I believe. Hope this helped
