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3 years ago

Fine the area of the regular figure

Mathematics

1 answer:

Sloan [31]3 years ago

7 0

Answer:

139.5 mm

Step-by-step explanation:

The area of a geometric shape with all sides of equal length is:

A (1/2)nsr

n = the number of sides

s = the length of the sides

r = the length of the apothem

The apothem is the line going from the center point of the shape to the middle of one of the sides.

A = (1/2)(5)(9)(6.2)

A = (1/2)279

A = 139.5 mm

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What is the standard form of 4 tens+ 6 tens

Allushta [10]

Is100 in standard form

4 0

4 years ago

Write four different expressions for the perimeter of a pentagon whose sides are all s-2 units long

igor_vitrenko [27]

Answer: The answers are given below.

Step-by-step explanation: Given that all the sides of a pentagon are (s-2) units long. This clearly tells us that the pentagon is a regular one with each side equal to (s-2) units.

We are to write the perimeter of the pentagon in four different expressions.

Let 'P' represents the perimeter of the pentagon.

Since it is a regular pentagon, we can write the perimeter in following four expressions.

P = (s-2) + (s-2) + (s-2) + (s-2) + (s-2),

= 5 × (s-2),

= 5s - 10,

= 5s - 5×2.

Thus, these are the four expressions for the perimeter of the pentagon.

6 0

3 years ago

A random sample of 20 healthy adults was collected and their body temperatures were measured in degrees Fahrenheit. The data can

castortr0y [4]

Answer:

Step-by-step explanation:

Hello!

You need to test the hypothesis that "the average temperature for healthy adults is not equal to 98.6"

The variable of interest is

X: The body temperature of a healthy adult. (Fahrenheit)

And the parameter of interest is the population mean, μ.

The statistic hypotheses are:

H₀: μ = 98.6

H₁: μ ≠ 98.6

α:0.05

Assuming that the variable has a normal distribution you have to use a one-sample t-statistic for this test.

Attached to the answer is the data of body temperature of n=19 healthy adults. Since you didn't copy the raw data for your exercise I'll use this to answer the question.

Using the data the sample mean and standard deviation are:

X[bar]= 98.12

S= 0.69

$t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~~t_{n-1}$

$t_{H_0}= \frac{98.12-98.6}{\frac{0.69}{\sqrt{19} } } = -3.03$

This test is two-tailed, using the critical value approach, you have the rejection region divided into two tails determined by two critical values:

$t_{n-1;\alpha /2}= t_{18;0.025}= -1.965$

$t_{n-1;1-\alpha /2}= t_{18;0.975}= 1.965$

Decision rule:

If $t_{H_0}$ ≤ -1.965 or if $t_{H_0}$ ≥ 1.965, the decision is to reject the null hypothesis.

If -1.965 < $t_{H_0}$ < 1.965, the decision is to not reject the null hypothesis.

The calculated statistic is less than the lower critical value, the decision is to reject the null hypothesis.

Using a significance level of 5%, there is enough evidence to reject the null hypothesis. Then you can conclude that the true mean body temperature for healthy adults is not equal to the traditional 98.6F.

I hope this helps!