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ozzi
2 years ago
6

PLEASE HELP ASAP 3/10/p=4/5/1/4

Mathematics
1 answer:
kati45 [8]2 years ago
6 0

Answer:

3

1

0

=

4

5

1

4

Step-by-step explanation:

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Multiply both sides of the original equation by x, and find the solution set of the new equation.
prisoha [69]

Answer: (0, 1) Usually, we put the solutions in parenthesis.

Step-by-step explanation: x(x+1) = x(2) which = x²+ x = 2x = x² + x - 2x = 0

x² - x = 0. Now we divide by x which = x(x - 1) = 0 and the new solution set is x = 0 and x -1 = 0 which equals x = 1

5 0
2 years ago
BRAINLIST pls Answer
Alex_Xolod [135]

Answer:

1 1/3 pound (1 pound and 1/3)

Step-by-step explanation:

u just but it in a fraction

4/3

and simplify to mixed number

1 1/3

4 0
3 years ago
Read 2 more answers
Write an equation in point-slope form for the line that passes through (6,4) with a slope of -4
Harman [31]

Step-by-step explanation:

<u>y</u> - <u>4</u> = -4

x - 6

y - 4 = -4x + 24

y = -4x + 24 + 4

y = -4x + 28

3 0
2 years ago
A company is producing two types of ski goggles. Thirty percent of the production is of type A, and the rest is of type B. Five
exis [7]

Answer:

\dfrac{14}{29}

Step-by-step explanation:

Let <em>P(A) </em>be the probability that goggle of type A is manufactured

<em>P(B) </em>be the probability that goggle of type B is manufactured

<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

<em>P(A)</em> = 30%

<em>P(B)</em> = 70%

<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

P(A \cap E) will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

P(B \cap E) will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

P(E \cap A) = P(A) \times P(E/A)

P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%

P(E \cap B) = P(B) \times P(E/B)

P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%

P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%

If a goggle is returned within 10 days of its purchase, probability that it was of type B:

P(B/E) = \dfrac{P(E \cap B)}{P(E)}

\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}

So, the required probability is \dfrac{14}{29}.

7 0
3 years ago
The mean and the median are the same.<br> 2,3,4,5
Ber [7]

Step-by-step explanation:

mean \: ( \bar  x) =  \frac{2 + 3 + 4 + 5}{4}  =  \frac{14}{4}  = 3.5 \\  \\ median \: =  \frac{3 + 4 }{2}  =  \frac{7}{4}  = 3.5 \\  \\

Thus, mean and median are same.

7 0
2 years ago
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