Answer:
A.99.7%
Step-by-step explanation:
We are given;
- Mean of a distribution, μ as 0.68 ounce
- Standard deviation, σ as 0.02 ounce
- The range values of X between 0.62 ounce and 0.74 ounce
We are required to calculate the percentage of the weight to be between 0.62 ounce and 0.74 ounce
Step 1: Calculate the Z-score
To get the Z-score we use the formula;
Z-score = (x-μ)/σ
Therefore, when x = 0.62
Then z score = (0.62 - 0.68 ) ÷ 0.02
= -3
When, x = 0.74
Then, Z score = (0.74 - 0.68) ÷ 0.02
= 3
Step 2: we use the Z-score table or the empirical rule
Using the Z-score table;
P(-3 < z < 3) = 99.7%.
Therefore; the percentage of mice that weigh between 0.62 ounce and 0.74 ounce is 99.7%.
Answer:
The third answer is correct
Step-by-step explanation:
Answer:
A and B
Step-by-step explanation:
using the law of exponents
• 
= 
, hence
= 
→ A
note that (- 3)² = 9 = 3², hence
= (3²)³ = 
→ B
Answer:
Step-by-step explanation:
Looking at the diagram,
Line DT is parallel to line line BM, therefore, triangle DHT is similar to triangle BHM. This means that
DH/DB = TH/MH
DH = 15 + 6 = 21
TH = 9 + x
Therefore
(9 + x)/21 = 9/6
Cross multiplying, it becomes
6(9 + x) = 21 × 9 = 189
54 + 6x = 189
Subtracting 54 from the left hand side and the right hand side of the equation, it becomes
6x + 54 - 54 = 189 - 54
6x = 135
Dividing the left hand side and the right hand side of the equation by 6, it becomes
6x/6 = 135/6
x = 22.5
