Answer:


Step-by-step explanation:

a) about the line y = 3
⇒
is the intersection point
So,

b) about the line x = 5
⇒ 
So,
![V = \int\limits^3_0\pi([5-0]^2-[5-y^2/9]^2)\:dy=\pi\int\limits^3_0(25-25+10y^2/9-y^4/81)\:dy=\\\\=\pi(10y^3/27-y^5/405)|^3_0=\pi(10-3/5)=\frac{47}{5} \pi](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5Climits%5E3_0%5Cpi%28%5B5-0%5D%5E2-%5B5-y%5E2%2F9%5D%5E2%29%5C%3Ady%3D%5Cpi%5Cint%5Climits%5E3_0%2825-25%2B10y%5E2%2F9-y%5E4%2F81%29%5C%3Ady%3D%5C%5C%5C%5C%3D%5Cpi%2810y%5E3%2F27-y%5E5%2F405%29%7C%5E3_0%3D%5Cpi%2810-3%2F5%29%3D%5Cfrac%7B47%7D%7B5%7D%20%5Cpi)
Answer:
-20u + 12y + 4
Step-by-step explanation:
We have the equation -4(5u - 3y - 1) and are asked to use the <u>distributive property</u> to remove the parenthesis.
When using the distributive property, you have to multiply the number outside the parenthesis to all numbers inside the parenthesis, do as followed :
-4(5u - 3y - 1)
(5u(-4) -3y(-4) -1(-4))
-20u + 12y + 4
Answer:all lines are straight
Step-by-step explanation:
Answer:
Step-by-step explanation:
6
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -8 ± √((8)^2 - 4(3)(2)) ] / ( 2(3) )
x = [-8 ± √(64 - (24) ) ] / ( 6 )
x = [-8 ± √(40) ] / ( 6)
x = [-8 ± 2*sqrt(10) ] / ( 6 )
x = -4/3 ± sqrt(10)/3
The answers are -4/3 + sqrt(10)/3 and -4/3 - sqrt(10)/3.