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Alexeev081 [22]
2 years ago
12

AABC ~ AQRS

Mathematics
1 answer:
Tasya [4]2 years ago
3 0

Answer:

Step-by-step explanation:

6

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A set of twins, Andrea and Courtney, are initially 10 years old. While Courtney remains on Earth, Andrea rides on a spaceship th
SVETLANKA909090 [29]

The initial age of 10 years and the spaceship speed of 0.60•c, gives the Andrea's age at the end of the trip as 18 years.

<h3>How can Andrea's new age be calculated?</h3>

The time dilation using the Lorentz transformation formula is presented as follows;

t' =  \frac{t}{ \sqrt{1 -  \frac{ {v}^{2} }{ {c}^{2} } } }

From the question, we have;

The spaceship's speed, <em>v</em> = 0.6•c

∆t = Rest frame, Courtney's time, change = 10 years

Therefore;

\delta t' =\delta t \times  \sqrt{1 -  \frac{ {(0.6 \cdot c)}^{2} }{ {c}^{2} } } = 8

The time that elapses as measured by Andrea = 8 years

Andrea's age, <em>A</em>, at the end of the trip is therefore;

A = 10 years + 8 years = 18 years

Learn more about the Lorentz transformation formula here:

brainly.com/question/15544452

#SPJ1

3 0
1 year ago
What is the slope of the line whose equation is -2/3y - = 0?
Lelechka [254]

Answer:

There is no slope, beacuse there is not a shown X

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Difference in elevation between mount Everest and Dead sea
Snowcat [4.5K]

The difference is 27, 735 ft


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2 years ago
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Which statement is true about numbers to the left of 0 on a number line?
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Numbers to the left of 0 on a number line or anywhere are always negative,

Step-by-step explanation:


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3 years ago
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Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

5 0
3 years ago
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