I need help on this home work

the cost of a ticket t to a concert with a 3% sales tax can be represented by the expression t+0.03t. simplify the expression. t

Leokris [45]

.03 time 72 then add 72 or just do 1.03 time 72

4 0

2 years ago

Mrs. Bergstedt teaches six classes. In her first period class she has 19 students, her third period she has 13 students, her fou

PilotLPTM [1.2K]

We find the average by adding up all the students and dividing them by the number of classes she has. 19 + 13 + 19 + 9 + 14 + 15 is 89, and that divided by 6 is approximately 14.8, rounded to the nearest tenth.
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Hope this helps!

3 0

3 years ago

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Location is known to affect the number, of a particular item, sold by an automobile dealer. Two different locations, A and B, ar

yKpoI14uk [10]

Answer:

We conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Step-by-step explanation:

We are given that Location A was observed for 18 days and location B was observed for 13 days.

On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4.

Let $\mu_1$ = true mean number of sales at location A.

$\mu_2$ = true mean number of sales at location B

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2\geq0$ or $\mu_1 \geq \mu_2$ {means that the true mean number of sales at location A is greater than or equal to the true mean number of sales at location B}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2$ or $\mu_1< \mu_2$ {means that the true mean number of sales at location A is fewer than the true mean number of sales at location B}

The test statistics that would be used here Two-sample t test statistics as we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n__1_-_n__2-2$

where, $\bar X_1$ = sample average of items sold at location A = 39

$\bar X_2$ = sample average of items sold at location B = 49

$s_1$ = sample standard deviation of items sold at location A = 8

$s_2$ = sample standard deviation of items sold at location B = 4

$n_1$ = sample of days location A was observed = 18

$n_2$ = sample of days location B was observed = 13

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(18-1)\times 8^{2}+(13-1)\times 4^{2} }{18+13-2} }$ = 6.64

So, test statistics = $\frac{(39-49)-(0)}{6.64 \times \sqrt{\frac{1}{18}+\frac{1}{13} } }$ ~ $t_2_9$

= -4.14

The value of t test statistics is -4.14.

Now, at 0.01 significance level the t table gives critical value of -2.462 at 29 degree of freedom for left-tailed test.

Since our test statistics is less than the critical values of t as -2.462 > -4.14, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

3 0

3 years ago

A cylinder and a cone have the same volume. the cylinder has a radius of 2 inches and a height of 3 inches. the cone has a radiu

Sati [7]

Answer:h = y^2 / 27

Step-by-step explanation:

Volume of a cylinder = pi*(xx)^2*yy

= x^4*pi*yy

Volume of a cone = 1/3*pi*(9x^2)^2*h

= 27pi*x^4*h

x^4*pi*y^2 = 27pi*x^4*h

h = y^2 / 27

4 0

3 years ago

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What value of c is needed to complete the square? X2 + 10x + c = -3+ c

Vikentia [17]

Answer:

Step-by-step explanation:Let's solve for c.

x2+10x+c=−3+c

Step 1: Add -c to both sides.

x2+c+10x+−c=c−3+−c

x2+10x=−3

Step 2: Add -x^2 to both sides.

x2+10x+−x2=−3+−x2

10x=−x2−3

Step 3: Add -10x to both sides.

10x+−10x=−x2−3+−10x

0=−x2−10x−3

Step 4: Divide both sides by 0.

0

=

−x2−10x−3

0

c=

−x2−10x−3

0

Answer:

c=

−x2−10x−3/0

hope it helps :D

4 0

3 years ago

I need help on this home work​

I need help on this home work