Help me with this please
1 answer:
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Answer:
d(x) = √[(x - 2)² + (3x - 1)²]
Step-by-step explanation:
The distance between two points with coordinates (x₁, y₁) and (x₂, y₂) is given as
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
So, the distance between point (2,0) and a point (x,y)
d = √[(x - 2)² + (y - 0)²]
d = √[(x - 2)² + (y)²]
But the point (x,y) is on the line y = 3x - 1
We can substitute for y in the distance between points equation.
d(x) = √[(x - 2)² + (3x - 1)²]
QED!
Answer:
i hope this helps
Step-by-step explanation:
2 -16=0
+16 +16
2 =16
÷2 ÷2
= 8
=
x=
-5 +9=0
-9 -9
-5=-9
÷-5 ÷-5
=1.8
=
x=
6 -15=27
+15 +15
6 =42
÷6 ÷6
=7
=
x=