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Bumek [7]
3 years ago
5

Can someone explain how to do these questions or show me how?

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0
Check the picture below.

bear in mind that since we have a radical in the denominator, we'd rationalize the denominator to take it off the denominator.

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Brita has a monthly budget of x dollars. She spends $1,425 on her mortgage every month. One-third of her remaining budget is spe
bazaltina [42]

Answer:

$(x - 1425)/3

Step-by-step explanation:

Let total monthly budget be x

Amount spent on mortgage = $1425

Remaining balance after spending on mortgage = x - $1425

Amount spent on recreational activities = one-third of the balance

Expressing amount spent on recreational activities as an equation will give;

Amount spent on recreational activities = 1/3 of x - $1425

= 1/3 × ( x - $1425)

= ( x - $1425)/3

Hence the required equation is;

R = $(x - 1425)/3

R means recreational activities

3 0
2 years ago
If f(x) = - 3x - 3. g(x) = 2x2 + 6x - 5. and h(x) = - 8x2 + 6. find f(-3). I REALLY NEED THIS ​
shepuryov [24]

Answer:

f(-3) = 6

Step-by-step explanation:

input -3 in f(x)

so f(-3) = -3(-3) - 3

multiple and add

f(-3) = 6

5 0
3 years ago
-2 (3 + 5y -10) = 34
IrinaK [193]
-2 (3+5y-10) = 34
Step 1) -6-10y+20=34
Step 2) -10y+20=40
Step 3) -10y=20
Step 4) y = -2
Answer is -2
7 0
3 years ago
Read 2 more answers
at a track meet,Jacob and daniel compete in 220 m hurdles. Daniels finishes in 3/4 of the a min.Jacob finishes with 5/12 of a mi
Savatey [412]
Jacob has the faster time because if you make the fractions equal you would make the denominators equal by rounding 3/4 to have a denominator of 12 making it 9/12 which is larger then 5/12 making Daniel's time slower then Jacob's.

3 0
3 years ago
Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
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