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Bumek [7]
3 years ago
5

Can someone explain how to do these questions or show me how?

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0
Check the picture below.

bear in mind that since we have a radical in the denominator, we'd rationalize the denominator to take it off the denominator.

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Two numbers multiply to be -7 and add to be -6. What are the numbers?<br><br> Example; 2,3
rewona [7]

<u>Given</u>:

Let the two numbers be x and y.

Two numbers multiply to be -7 and add to be -6.

This can be written in equation as,

xy=-7 and

x+y=-6

<u>Value of the two numbers:</u>

Let us determine the value of the two numbers using substitution method.

Substituting y=-6-x in the equation xy=-7, we get;

x(-6-x)=-7

Simplifying, we get;

       -6x-x^2=-7

   x^2+6x-7=0

(x+7)(x-1)=0

x=-7, 1

Thus, the values of x are x = 1,-7

When x = 1 , the equation x+y=-6 becomes y=-7

When x = -7, the equation x+y=-6 becomes y=1

Therefore, the two numbers are 1 and -7

3 0
3 years ago
List the integers that satisfy both these inequalities, 2x+9 -12
Flura [38]

Answer:

x < -10.5

Step-by-step explanation:

list the integers that satisfy both these inequalities, 2x+9 <-12

Subtract 9 from  both sides;

2x +9 - 9 < -12-9

2x < -21

x < -21/2

x < -10.5

<em>Hence all the integers are values of x less than 10.5</em>

<em></em>

4 0
3 years ago
10^1 has what place value?
Oxana [17]
It is in the ten's place. hope that helped
6 0
3 years ago
Read 2 more answers
You are given f(0) = 1 and g(0) = -2 and g(1) = 3. What is <br> g ∘ f ( 0 ) <br> equal to?
Sergeu [11.5K]

Answer:

  • <u><em>g∘f (0) = 1</em></u>

Explanation:

The <em>composition</em> of the <em>functions</em> f and g represented by g ∘ f ( 0 ) means that g is applied to f(0), i.e f(0) is the input to the function g.

Since f(0) = 1, you are going fo find g(1):

         \( g\circ f(x)=g(f(x)) \)\\\\\( g\circ f(0)=g(f(0)) \)\\\\\( g\circ f(0)=g(1) \)=3

4 0
3 years ago
What is AxD = ?????????????
storchak [24]

Answer:

AD

Step-by-step explanation:

AxD= AD

3 0
3 years ago
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