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3 years ago

Given the function f(x) = 0.5|x – 4| – 3, for what values of x is f(x) = 7?

Mathematics

1 answer:

Semenov [28]3 years ago

5 0

Answer:

x = - 16, x = 24

Step-by-step explanation:

Given f(x) = 7 then equate f(x) to 7

0.5 | x - 4 | - 3 = 7 ( add 3 to both sides )

0.5 | x - 4 | = 10 ( divide both sides by 0.5 )

| x - 4 | = 20

The expression inside the absolute value bars can be positive or negative, so

x - 4 = 20 ( add 4 to both sides )

x = 24

- (x - 4) = 20

- x + 4 = 20 ( subtract 4 from both sides )

- x = 16 ( multiply both sides by - 1 )

x = - 16

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Degger [83]

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2 years ago

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cricket20 [7]

Answer:

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Step-by-step explanation:

Ren has 27 cards, which is 13 more than what Chet has. So you subtract. 27-13=14.

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3 years ago

Length=x^2 -8; W= -x+12 <br><br><br> PLEASE HELP!

ASHA 777 [7]

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3 years ago

The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c

Slav-nsk [51]

$\text{Answer} : \text{The expected value of a t-shirt is \$31.}$

Explanation:

Since we have given that

The prices of three t-shirts styles i.e $24, $30, $36 with their probability is given by

$\frac{1}{6}, \frac{1}{2},\frac{1}{3}$

As we know that,

$E(X)= \sum_{1}^{3}x_iP(x_i)$

$\text{where} x_i \text{ is the prices of t- shirts styles}$

Now,

$x_1= \$24 , x_2=\$30 , x_3=$36$

and

$P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}$

So,

$E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31$

So, the expected value of a t-shirt = $31.

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3 years ago

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Ahat [919]

The ordered pairs are (1,-1) (1,-2) (2,-3) (2,-4).

This is not a function because in order to be a function, every x value needs to have one and only one y value. You can see here that the x values have two y values, so it is not a function.

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3 years ago