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ololo11 [35]
3 years ago
15

Decide whether the numbers can represent the side lengths of a triangle. If they can, classify the triangle as right, acute, or

obtuse.
(pls help me im desperate for an answer for 5, 6, 7, and 8)

Mathematics
1 answer:
Irina18 [472]3 years ago
7 0

Answer:

4) i) The numbers can represent the side lengths of a triangle

ii) Right triangle

5) i) The numbers can represent the side lengths of a triangle

ii) Isosceles triangle

6) i) The numbers can represent the lengths of the sides of a triangle

ii) Pythagoras theorem

7) The numbers do not represent the lengths of sides of a triangle

8) i) The numbers can represent the side lengths of a triangle

ii) Scalene triangle

Step-by-step explanation:

In a triangle, the sum of the lengths of the two shorter sides is longer than the length of the longest side

The given numbers are;

4) i) 15, 20, 25

Given that 15 + 20 < 25, the numbers can represent the side lengths of a triangle

ii) 15² + 20² = 25²

Therefore, the sides lengths are in line with the side length of a right triangle as their relation is given by Pythagoras theorem

The triangle is a right triangle

5) i) The given numbers are;

2, 6, 6

Given that 2 + 6 > 6, the numbers can represent the side lengths of a triangle

ii) Given that the lengths of two sides are equal (6 each), the triangle formed by the numbers is an isosceles triangle

6) i) 0.27, 0.36, 0.45

0.27 + 0.36 = 0.63 > 0.45, therefore, the numbers can represent the lengths of the sides of a triangle

ii) Given that 0.27² + 0.36² = 0.45², according to Pythagoras theorem, the type of triangle formed is a right triangle

7) 2.5, 1.5, 4

Given that 2.5 + 1.5 = 4, the numbers do not meet the criteria for forming triangles and therefore they cannot represent the side lengths of a triangle

8) i) 12,  16, 25

12 + 16 = 28 > 25, the numbers can represent the side lengths of a triangle

ii) 12² + 16² = 400 < 25² = 625, therefore, the triangle formed by the numbers is not a right triangle but a scalene triangle.

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using the tangent ratio: 

tan</span>Θ = opposite / adjacent
<span>
tan7º = 663 m / x 

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Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

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In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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0.95 probaiblity of hitting a target

This means that p = 0.95

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This means that n = 10

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Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

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40.1% probability that he will miss at least one of them

7 0
3 years ago
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Step-by-step explanation:

<em>ok</em><em>,</em><em> so just let me</em><em>,</em><em> uh</em><em>,</em><em> make this a little easier on my eyes lol:</em>

-10m^4n^3+8m^2n^6-6m^2n^6 ----> (-10m^4)(n^3) + (8m^2)(n^6) - (6m^2)(n^6)

<em>I just put in parentheses. nothing changed. just parentheses. </em>

Since the leading coefficients, -10 , 8 , and 6 are multiples of two,

we can take out 2 from each... [-10/2 = 5 , 8/2 = 4 , 6/2 = 3 ]

= 2 x [ (-5m^4)(n^3) + (4m^2)(n^6) - (3m^2)(n^6) ]

Looking at it now...

<em>we can take out m^2 from each... </em>m^4 , m^2 , and m^2

m^2 [m^2 , 1 , 1]

since    m^4 /m^2 = m^2 , m^2 /m^2 = 1 , m^2 /m^2 = 1

= 2(m^2) x [ (-5m^2)(n^3) + (4x1)(n^6) - (3x1)(n^6) ]

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Finally, one more step...

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n^3 [1 , n^2 , n^2] since n^3 /n^3 = 1 , n^6 /n^3 = n^2 , n^6 /n^3 = n^2

= 2(m^2)(n^3) [ (-5m^2)(1) + (4)(n^2) - (3)(n^2) ]

= 2m^2n^3 x [ (-5m^2) + (4n^2) - (3n^2) ]

= 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )

ANSWER: 2m^2n^3 x ( -5m^2 + 4n^2 -3n^2 )

<em>keep this parentheses. seriously. </em>

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