Answer:
The c++ program to implement search through an array is shown.
#include <iostream>
using namespace std;
int main()
{
int sequence[10] = { 3, 4, 5, 6, 7, 8, 9, 10, 1, 2 };
int input;
int found = 0;
cout << " This program confirms whether your element is present in the array. " << endl;
cout << " Enter any number " << endl;
cin >> input;
for( int k = 0; k < 10; k++ )
{
if( input == sequence[k] )
found = found + 1;
}
if( found == 0 )
cout << " Not Found " << endl;
else
cout << " Found " << endl;
return 0;
}
OUTPUT
This program confirms whether your element is present in the array.
Enter any number
7
Found
Explanation:
The program uses the given integer array.
User is prompted to input any number. No validation is implemented for user input since it is not mentioned. The user input is taken in an integer variable, input.
int input;
cout << " Enter any number " << endl;
cin >> input;
Another integer variable found is declared and initialized to 0.
int found = 0;
Inside for loop, each element is compared with the user input.
If the user input is present in the given array, variable found is incremented by 1.
for( int k = 0; k < 10; k++ )
{
if( input == sequence[k] )
found = found + 1;
}
If value of variable found is 0, program displays “ Not Found ”.
If the value of variable found is greater than 0, program displays “ Found ”.
if( found == 0 )
cout << " Not Found " << endl;
else
cout << " Found " << endl;
This program can be tested for both positive and negative numbers.
