Question

PLS PLS PLS HELP i dont get it

Answer 1

we are looking for an equation perpendicular to y = -2x + 5

The form: y = mx + b

Where m is the pending; and b is the product of X1 for m, add the Y1

The pending of a line that is perpendicular to other line is reprical to the pending ot this other line, and with a different sign.

So, the pending of this first line is -2, the reprical is -1/2. We change the sing and we have 1/2

The second line does have a pending of 1/2 (0.5).

So, this second line pass for the point (0,0), so we have the equation:

y - Y1 = m(x - X1)

Where Y1 and X1 are the points y and x where pass the line.

If the line pass for the points 0 and 0, so:

y - 0 = m(x - 0)

And the pending we know is 0.5, so

y - 0 = 0.5(x - 0)

We pass to the form slop-intercept:

y = 0.5x - (0.5*0) + 0

The same that:

y = 0.5x

Cause 0+0=0