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2 years ago

How do I find the area of a circle when the circumference is 58 pie

Mathematics

2 answers:

aksik [14]2 years ago

8 0

C=2 $\pi$ r
A= $\pi$ r<span>²

C=2</span> $\pi$ r=58 $\pi$
2r=58
r=29

A= $\pi$ r<span>²
A=29</span><span>²</span> $\pi$
A=841 $\pi$

alexgriva [62]2 years ago

8 0

C=πd
58π=πd
We conclude that
d=58 cm
r=1/2d
r=58(1/2)
r=29 cm
A=πr^2
A=29^2π
A=841π
Or
A≈2640.74 square cm. Hope it help!

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The best estimate is 27 dollars.

Step-by-step explanation:

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nikitadnepr [17]

Answer:

a = 6.94

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3 years ago

Read 2 more answers

1. D=5.9 ft.

Shtirlitz [24]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Here's the solution ~

As we know, we can calculate the circumference of a circle in terms of its diameter as :

$\qquad \sf \dashrightarrow \:c = \pi d$

where, c = circumference and d = diameter

And also, circumference of circle is terms of radius (r) is :

$\qquad \sf \dashrightarrow \:c = 2\pi r$

Now, let's move on to questions ~

<h3>First </h3>

$\qquad \sf \dashrightarrow \:3.14 \times 5.9$

$\qquad \sf \dashrightarrow \: \approx18.53 \: ft$

<h3 />

・．━━━━━━━†━━━━━━━━━．・

<h3>Second</h3><h3 /><h3 /><h3 /><h3> $\qquad \sf \dashrightarrow \:3.14 \times 3.2$ </h3>

$\qquad \sf \dashrightarrow \: \approx10.048 \: ft$

・．━━━━━━━†━━━━━━━━━．・

<h3>Third</h3>

$\qquad \sf \dashrightarrow \:3.14 \times 6.1$

$\qquad \sf \dashrightarrow \: \approx19.15 \: ft$

・．━━━━━━━†━━━━━━━━━．・

<h3>Fourth</h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 3.7$

$\qquad \sf \dashrightarrow \: \approx2×11.62 \: m$

$\qquad \sf \dashrightarrow \: \approx23.24 \: m$

・．━━━━━━━†━━━━━━━━━．・

<h3>Fifth </h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 6.2$

$\qquad \sf \dashrightarrow \: \approx2× 19.47 \: units$

$\qquad \sf \dashrightarrow \: \approx38.94 \: m$

・．━━━━━━━†━━━━━━━━━．・

<h3>Sixth</h3>

$\qquad \sf \dashrightarrow \:2×3.14 \times 5.1$

$\qquad \sf \dashrightarrow \: \approx2×16.01 \: ft$

$\qquad \sf \dashrightarrow \: \approx \: 32.02m$

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

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and

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To understand the transformed rule, just remove the coordinates of the actual polygon from the transformed polygon.

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Similarly,

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