1. Area of a circle is pi(R)^2 , where R is the radius. So we can substitute:
22/7(16^2) = about 805 meters squared.
2. Let's find the area of the rectangle first.
A=LW
A= 18(10)
A= 180 cm squared.
Now the semi-Circle:
The radius of the circle is 9 (because 18/2 is 9). Now we plug in to the area formula:
22/7(9^2) = about 254 cm squared. But because that is the area of the whole circle, and we only need half of the circle, we divide that value by 2 to get:
127 cm squared for the semi-circle.
Now we add up the rectangle and semi-circle's areas:
180 + 127 = 307 cm squared as your answer.
I hope this Helps!
Distance1 ÷ (Jaime's velocity + wind velocity) =
Distance2 ÷ (<span>Jaime's velocity - wind velocity)</span>
57 / (Jaime's velocity + 4) = 33 / (<span>Jaime's velocity -4)
</span>
57 / 33 = (Jaime's velocity + 4) / (Jaime's velocity - 4)
(57 * -4) +57 * (Jaime's velocity) = (33 * 4) +33 * (Jaime's velocity)
-228 + 57 JV = 132 + 33 JV
24 JV = 360
Jaime's velocity = 15
Source
http://www.1728.org/veloccal.htm
(see Problem E)
To find the answer for x, you have to use the pythagoryen theorem. The line AC is 16 inches, but the little segment of the triangle is 4 inches. So first, you have to use the pythaoryen theorem and get this equation: CB plus AB=16 inches. Once you find CB, use it again to find the value of DB. DB plus DC equals CB. Then DB = X.
The length of the side opposite the smallest angle of the triangle is 2.00 <span>centimeters</span>
Answer:
48
Step-by-step explanation:
12*4=w=48
