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3 years ago

You roll a six-sided die. How likely is it that you roll a number greater than 6?

Mathematics

2 answers:

Levart [38]3 years ago

6 0

Answer:

impossible

dices / a die has only 6 sides, so it has 6 numbers

1,2,3,4,5,6

IrinaVladis [17]3 years ago

3 0

It is impossible to roll a number greater than 6

You might be interested in

What is the trigonometric ratio for sin C ?<br><br> Enter your answer, as a simplified fraction.

Contact [7]

By definition we have to:
Sin (x) = C.O / h
Where,
x = angle
C.O = opposite leg
h: hypotenuse.
Substituting values we have:
Sin (C) = AB / 82
We should look for AB. For this, we use the following relationship:
AB ^ 2 + 80 ^ 2 = 82 ^ 2
Clearing AB:
AB = root ((82 ^ 2) - (80 ^ 2))
AB = 18
Substituting we have:
Sin (C) = 18/82
Simplifying:
Sin (C) = 9/41

Answer:
the trigonometric ratio for sin C is:
Sin (C) = 9/41

5 0

3 years ago

The ratios in an equivalent ratio table are 3:12, 4:16, and 5:20. If the first number in theratio is 10, what is the Second numb

Zanzabum

Answer:

10:40

Step-by-step explanation:

As the left number increases by 1, the right number increases by 4. So as you can see, the left numbers go 3-4-5 while the right numbers go 12-16-20. So the answer is 10:40 because 10x4=40.

6 0

3 years ago

Read 2 more answers

Urgent answer needed pls

worty [1.4K]

Answer:

48 cm²

Step-by-step explanation:

PTRS is parallelogram with the base length= 8cm and the height as same as the height of ∆SUR.

the height = 2×24/8 = 6cm

so, the area of PTRS= 8×6 = 48 cm²

6 0

3 years ago

Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets for a flight that holds only 12

melamori03 [73]

Answer:

98.75% probability that every passenger who shows up can take the flight

Step-by-step explanation:

For each passenger who show up, there are only two possible outcomes. Either they can take the flight, or they do not. The probability of a passenger taking the flight is independent from other passenger. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .