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Alexxx [7]
3 years ago
14

What is the length of BC in the right triangle below?

Mathematics
2 answers:
allochka39001 [22]3 years ago
4 0

Answer:

Option A

Step-by-step explanation:

Use the Pythagoras Theorem

Hypotaneous² = base² + height²

BC² = AB² + AC²

BC = √ (AB² + AC²)

BC =  √ (12² + 16²)

BC = 20

Alla [95]3 years ago
4 0

Answer:

<em>2</em><em>0</em>

Step-by-step explanation:

<em>Here's</em><em> </em><em>your</em><em> solution</em>

<em>=</em><em>></em><em> </em><em>in </em><em>a </em><em>right</em><em> </em><em>angle</em><em> </em><em>traingle</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em>BC^</em><em>2</em><em> </em><em>=</em><em> </em><em>AB^</em><em>2</em><em> </em><em>+</em><em> </em><em>AC^</em><em>2</em>

<em>=</em><em>></em><em> </em><em>BC^</em><em>2</em><em> </em><em>=</em><em> </em><em>1</em><em>6</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>1</em><em>2</em><em>^</em><em>2</em>

<em>=</em><em>></em><em> </em><em>BC </em><em>^</em><em>2</em><em> </em><em>=</em><em> </em><em>2</em><em>5</em><em>6</em><em> </em><em>+</em><em> </em><em>1</em><em>4</em><em>4</em>

<em> </em><em>=</em><em>></em><em> </em><em>BC^</em><em>2</em><em> </em><em>=</em><em> </em><em>4</em><em>0</em><em>0</em>

<em>=</em><em>></em><em> </em><em>BC </em><em>=</em><em> </em><em>√</em><em>4</em><em>0</em><em>0</em>

<em>=</em><em>></em><em> </em><em>BC </em><em>=</em><em> </em><em>2</em><em>0</em>

<em>hope</em><em> it</em><em> helps</em>

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