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Sergio039 [100]
3 years ago
8

The following graph models bristols heart rate, in beats per minute(bpm), over time, in minutes during the last 10 minutes of yo

ga class. Bristols heart rate is 70.
Is the graph that models Bristol's heart rate a parabola?

Mathematics
2 answers:
Alexxandr [17]3 years ago
8 0
Yes, this is a parabola; it is a u-shaped graph.

The vertex is at (5, 120), and each corresponding point on either side of the graph is the same distance from the vertex.
erastova [34]3 years ago
3 0

Answer:

Yes. This is a parabola

Step-by-step explanation:

Yes. This is a parabola.

Reasons:

I. It is open down

2. Symmetrical about a vertical line

3. Has a vertex

4. Any point on the curve is equidistant from a point and a line.

Hence parabola

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Answer:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

ME represent the margin of error

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

2) Solution to the problem

Since the new Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Assuming that the deviation is known we can express the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =\pm 3 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

Replacing into formula (b) we got:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

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The symbol is π (pi)

No matter how large or small the circle, its circumference is always π times its diameter.

π = 3.14159265358979323846... (the digits go on forever without repeating)

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