The weight of oranges growing in an orchard is normally distributed with a mean weight of 7 oz. and a standard deviation of 1.5
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Answer:
a) Percentage of students scored below 300 is 1.79%.
b) Score puts someone in the 90th percentile is 638.
Step-by-step explanation:
Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.
(a) If the average test score is 510 with a standard deviation of 100 points.
To find : What percentage of students scored below 300 ?
Solution :
Mean ,
Standard deviation
Sample mean
Percentage of students scored below 300 is given by,
Percentage of students scored below 300 is 1.79%.
(b) What score puts someone in the 90th percentile?
90th percentile is such that,
Now,
Score puts someone in the 90th percentile is 638.