The answer is A= 3.14(r· squared)
<span>f(x)=5(x+4)^3/2, let y = f(x).
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<span>y =5(x+4)^3/2. The y intercept is value of y when x = 0
y intercept = </span><span>5(0+4)^3/2 = 5* 4^3.2 = 5*6 = 30. Use your calculator.
y intercept = 30
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All three triangles are congruent by SAS
Plot the sets of (x,y)
begin connecting the points until it says stop
when it says stop you will not connect the last point you graphed to the new point
so just plot the (x,y) connect the points and when it says stop you will start a connecting another set of points
What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²