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deff fn [24]
3 years ago
11

In which figure is the height of the cylinder half the radius? A cylinder with a height of 2 and diameter of 8. A cylinder with

a height of 4 and diameter of 8. A cylinder with a height of 8 and diameter of 8. A cylinder with a height of 16 and diameter of 8. Mark this and return
Mathematics
2 answers:
aliya0001 [1]3 years ago
6 0
A cylinder with a height of 2 and a diameter of 8. Please mark brainliest.
mr_godi [17]3 years ago
5 0

Answer:

The correct answer is A

Step-by-step explanation:

I took the test

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Matrices A and B are shown below.
BabaBlast [244]
The first thing you must remember is that the product of matrices is done by multiplying rows by columns.
 For this case, the AB matrix is
 AB = [1 0 0; 0 1 0; (x + 1) 0 y]
 Equalizing the identity matrix we have
 AB = I
 [1 0 0; 0 1 0; (x + 1) 0 y] = [1 0 0; 0 1 0; 0 0 1]
 Therefore we have
 x + 1 = 0
 y = 1
 The values of x and y are
 x = -1
 y = 1 
the answer is 
 X=-1
 Y=1
8 0
4 years ago
14 + 2(x – 3) = 4(x + 4)
strojnjashka [21]

Answer:

x= -4

Step-by-step explanation:

distribute

combine like terms

subtract 4x from both sides

subtract 8 from both sides

divide both sides by -2

7 0
3 years ago
Read 2 more answers
Geometry help anyone!!
olya-2409 [2.1K]

Answer: b

Step-by-step explanation:

4 0
3 years ago
I NEED HELP ON THIS PROBLEM!!! PLEASE
Allushta [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

5x+8y=-9\implies 8y=-5x-9\implies y=\cfrac{-5x-9}{8} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{5}{8}} x-9\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

well then, so since this equation has that slope therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{-5}{8}} ~\hfill \stackrel{reciprocal}{\cfrac{8}{-5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{8}{-5}\implies \cfrac{8}{5}}}

so we're really looking for the equation of a line whose slope is 8/5 and runs through (10,10)

(\stackrel{x_1}{10}~,~\stackrel{y_1}{10}) ~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{8}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{\cfrac{8}{5}}(x-\stackrel{x_1}{10})

5 0
2 years ago
What is the expected value of X?
Soloha48 [4]

Answer:

5.6

Step-by-step explanation:

fr fr

7 0
4 years ago
Read 2 more answers
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