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cupoosta [38]
3 years ago
13

The equation y=2(x-1)^2-5y=2(x−1)

Mathematics
1 answer:
marin [14]3 years ago
8 0

Answer:

(b) It is symmetrical about x = 1

Step-by-step explanation:

Given

y = 2(x - 1)^2 - 5

See attachment for options

Required

True statement about the graph

First, we check the line of symmetric

y = 2(x - 1)^2 - 5

Expand

y = 2(x^2 - 2x + 1) - 5

Open bracket

y = 2x^2 - 4x + 2 - 5

y = 2x^2 - 4x -3

A quadratic equation y = ax^2 + bx + c has the following line of symmetry

x = -\frac{b}{2a}

By comparison, the equation becomes:

x = -\frac{-4}{2*2}

x = \frac{4}{4}

x = 1

Hence, the line of symmetry is at: x = 1

(b) is true.

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