3x - 6 = 4x + 1
3x - 6 + 6 = 4x + 1 + 6
3x = 4x + 7
3x - 4x = 4x + 7 - 4x
X = -7
:)
Commutative says you can add or multiply in any order
basically goes like this
a+b=b+a or
ab=ba
so what we need is something where the order change, nothing else
first one: (4+3)+x=(3+4)+x, the order changed, correct
2nd
ab=ba, this is not addition
3rd
r+(s+t)=(r+s)+t this is associative property
4th
n+0=n
this is zero addition property
answer is first one
<h3>
Answer: Q = 8</h3>
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Explanation:
The left hand side of the first equation is x-3y
The left hand side of the second equation is 2x-6y = 2(x-3y). Note how it's simply double of the first expression x-3y
If we multiply both sides of the first equation by 2, we get
x-3y = 4
2(x-3y) = 2*4
2x-6y = 8
Meaning that 2x-6y = 8 is equivalent to x-3y = 4. Both produce the same line leading to infinitely many solutions. Each solution will lay along the line x-3y = 4.
We can say each solution is in the set {(x,y): x-3y = 4}
Which is the same as saying each solution is of the form (3y+4,y)
There is an example hope it helped
Answer:
The cost would be same after 3 months.
Step-by-step explanation:
Given that:
Charges of first company;
Sign up fee = $76
Per month charges = $40
Let,
x be the number of months
y be the total cost.
y = 40x + 76 Eqn 1
Charges of second company;
Sign up fee = $136
Per month charges = $20
y = 20x + 136 Eqn 2
For same cost,
Eqn 1 = Eqn 2
40x + 76 = 20x + 136
40x-20x = 136 - 76
20x = 60
Dividing both sides by 20
Hence,
The cost would be same after 3 months.
