Answer:Magnitude of voltage is 41.9963 volts
Step-by-step explanation:
Given that current I =5.772-5.323i mA
and impedance, Z=3.342+4.176i kilo ohms
Then voltage in the circuit = IZ
![=(5.772-5.323i)X10^{-3}X(3.342+4.176i)X10^{3}](https://tex.z-dn.net/?f=%3D%285.772-5.323i%29X10%5E%7B-3%7DX%283.342%2B4.176i%29X10%5E%7B3%7D)
![V=(5.772-5.323i)X(3.342+4.176i)](https://tex.z-dn.net/?f=V%3D%285.772-5.323i%29X%283.342%2B4.176i%29)
![V=19.290024+24.103872i-17.789466i-23..5148848i^{2}](https://tex.z-dn.net/?f=V%3D19.290024%2B24.103872i-17.789466i-23..5148848i%5E%7B2%7D)
![V=41.518892+6.314406i](https://tex.z-dn.net/?f=V%3D41.518892%2B6.314406i)
Magnitude of V = ![\sqrt{41.518892^{2} +6.314406^{2} }=\sqrt{1763.6901}=41.9963volts](https://tex.z-dn.net/?f=%5Csqrt%7B41.518892%5E%7B2%7D%20%2B6.314406%5E%7B2%7D%20%7D%3D%5Csqrt%7B1763.6901%7D%3D41.9963volts)
Answer:
16 serving.
Step-by-step explanation:
Given: 3/4 cup servings.
Now, computing the number of serving in 12 cups of cherries.
Using unitary method to solve.
∴ Number of serving= ![total\ cups \times number\ of\ serving\ per\ cup](https://tex.z-dn.net/?f=total%5C%20cups%20%5Ctimes%20number%5C%20of%5C%20serving%5C%20per%5C%20cup)
Number of serving in one cup is ![\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D)
Number of serving in 12 cups = ![12\times \frac{4}{3} = 16 \ serving](https://tex.z-dn.net/?f=12%5Ctimes%20%5Cfrac%7B4%7D%7B3%7D%20%3D%2016%20%5C%20serving)
Number of serving in 12 cups= ![16\ serving](https://tex.z-dn.net/?f=16%5C%20serving)
∴ There are 16 serving is possible in 12 cups of cherries.
Answer:
224
Step-by-step explanation:
You can simplifying 24/3 by dividing 24 by 3.
24÷3=8
The answer is 8.