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3 years ago

Can u give me the solution step by step

Mathematics

1 answer:

enot [183]3 years ago

4 0

The answer to the question is C. To find that you have to solve each equation.

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Use common denominators to determine whether the ratios form a proportion.

AURORKA [14]

They are not in proportion, since its 6:9 round it down (2:3) so pretend the 6 are apples and the 9 are oranges

Every 2 apples there are 3 oranges

So having 9 apples what is that?

2 x ? = 9

2 x 4.5 = 9

So if you want to keep 2:3 you have you times the oranges by 4.5 aswell!

3 x 4.5 = 13.5

So since it is 9:12 not 9:13.5 they are not in proportion

7 0

3 years ago

Read 2 more answers

Which statement describes the graph?

max2010maxim [7]

Answer : D

From the given graph , we can see that

The graph crosses the y axis at 7

So y axis is (0,7)

The graph is increasing at first and reaches (-2,8) and then start decreasing

The graph start increasing at x=-10 and goes on increasing till x= -2

then the graph start decreasing at x=-2 and goes in decreasing till x= 10

The graph crosses the y axis at (0,7), increasing from x=-10 to x=-2 and decreasing from x=-2 to x=10

Answer D is correct

6 0

3 years ago

Read 2 more answers

Using the function A(t)=P(1=r/n)^nt, create the function that represents your new car loan that is compounded monthly. The princ

-BARSIC- [3]

What does each variable represent?

6 0

3 years ago

Tyler brother works in a shoe store and the store brought a pair of shoes for $50 and sold it for $80 what percentage was the ma

Free_Kalibri [48]

Answer:

$60.

Step-by-step explanation:

Cost price= $50

Selling price = $80

Percentage markup = Gain/Cost price x 100%

=30/50x100

=$60.

7 0

2 years ago

Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f

Korvikt [17]

If there is some scalar function $f(x,y)$ such that

$\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j$

then we want to find $f$ such that

$\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)$
$\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C$
$\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C$

So the vector field $\mathbf f(x,y)$ is conservative, which means the fundamental theorem applies; the line integral of $\mathbf f$ along any path $\mathcal C$ parameterized by some vector-valued function $\mathbf r(t)$ over $a\le t\le b$ is given by

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))$

In this case,

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(1,2)-f(-1,2)=\dfrac23$

5 0

3 years ago