Answer:
sry I can't understand how to do this question
9514 1404 393
Answer:
b) y=(x+6)^2-32
Step-by-step explanation:
Add and subtract the square of half the x-coefficient to put into vertex form.
f(x) = x^2 +12x +4 . . . . . given
y = x^2 +12x +36 +4 -36 . . . . add and subtract (12/2)^2 = 36
y = (x +6)^2 -32 . . . . . . . . . . . write in vertex form
- 12 + x ≥ 3 (x - 6)
- or, 12 + x ≥ 3x - 18
- or, 12 + 18 ≥ 3x - x
- or, 30 ≥ 2x
- or, 30/2 ≥ x
- or, 15 ≥ x
- or, x ≤ 15
<u>Answer</u><u>:</u>
<em><u>x </u></em><em><u>≤</u></em><em><u> </u></em><em><u>1</u></em><em><u>5</u></em>
Hope you could get an idea from here.
Doubt clarification - use comment section.
I’d say the second one, the fourth one and the fifth one.
Hope it works :)
