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Nata [24]
3 years ago
14

Help me plz if you can

Mathematics
1 answer:
posledela3 years ago
6 0

Answer:

The first problem the answer is x= -25/4

Step-by-step explanation:

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there are 60 fish in the pond. use your experimental probability to predict how many are pink salmon, yellowfin tuna and blue gi
Talja [164]

Answer: I got it right on the tutorial

Step-by-step explanation:

Pink salmon: 25

Yellowfin Tuna: 0

Bluegill: 25

5 0
3 years ago
Evaluate the algebraic expression.<br> z^2+1+y when y=4, and z=3.
Luden [163]

Answer:

your question is

z²+1+y where, y=4,z=3

3²+1+4

9+5

14

is your answer

5 0
2 years ago
Please help me, I will be so thankful ​
worty [1.4K]

Answer:

Step-by-step explanation:

g(-4) = 4   ,  x < -2

g(-2) = (x - 1)²     ; -2≤x< 1

        = (-2-1)²

         = (-3)²

g(-2) = 9

g(0) = (x -1)²      ;  -2 ≤ x < 1

      = (0 -1)²

       = (-1)²

       = 1

8 0
3 years ago
Over the summer, Janice spent 120 hours reading. She
zalisa [80]

Answer:

time spent reading science fiction= 18

time spent reading non-fiction=102

Step-by-step explanation:

15 percent off 120.00 is 102.00 The difference is 18.00

6 0
3 years ago
0 = -1/14 x^2 + 4x +5<br><br> I need to solve for x but I don't get it, PLEASE EXPLAIN AND HELP!!
MariettaO [177]
Any time you have a fraction within an equation, multiply the entire equation by the denominator to clear the fraction. Since the lead term is negative, we can multiply that away as well
(-14) (0=-1/14x²+4x+5)      [now distribute]

0=x²-56x+70      [try to factor into binomials first]
Since 70 only has prime factors of 2·5·7, there is no combination which equals (-56). Use the quadratic formula, or complete the square. I'll use quadratic:

x=<u>-b+/-√(b²-4ac)</u>
            2a
a=1, b=(-56), c=70

x= <u>-(-56)+/- √((-56)²-4(1)(70)</u>
                  2(1)
x= <u>56+/- √(3136-280)
</u>               2
<u />x=<u>56+/-√(2856)</u>
             2
x=<u>56+/-√(2³·3·119)</u>
               2

x=<u>56+/-2√(714)</u>
             2

x=28+√714; x=28-√714



5 0
3 years ago
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