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Tresset [83]
3 years ago
9

Plz help asap for brainiest

Mathematics
2 answers:
Sergio [31]3 years ago
7 0

Answer: x = 16

Step-by-step explanation:

If RQ is the bisector, that means the angle is cut in half. Therefore angles PRQ and QRS are equal to each other.

4x+6 = 7x-42

subtract 7x from both sides

-3x+6 = -42

subtract 6 from both sides

-3x = -48

divide both sides by -3

x = 16

Feliz [49]3 years ago
6 0

Answer:

x=16

if prq and qrs have the same degree

Step-by-step explanation:

Branilest plaese

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the perimeter of the top of a desk is 54 inches if the length of the desk is 15 inches what is the width of the desk
nexus9112 [7]
54-15=39
if you want to check your answer you add 39+15=54

6 0
3 years ago
Read 2 more answers
Find the value of x.
sp2606 [1]

x = 64°

Step-by-step Explanation

x = 1/2[(360° - 2*58°)-2*58°]

x = 1/2[(360° - 2*58°) - 2*58°]

x = 1/2[(360° - 116°) - 116°]

x = 1/2[244° - 116°]

x = 1/2[128°]

x = 64°

8 0
3 years ago
Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0
3 years ago
4(2k-3)+1=8k-11 help pls
Fofino [41]
4(2k - 3) + 1 = 8k - 11
8k - 12 + 1 = 8k - 11
8k - 11 = 8k - 11

So, these two equations equal to the same thing.
Glad I could help and gave a fantastic day!
8 0
3 years ago
What is the solution for the quadratic equation?
N76 [4]
B since you can rewrite it as (2x+7)(x-4)=0 and you can solve it and you get B
7 0
3 years ago
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