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I am Lyosha [343]
3 years ago
14

Kristen is calculating the quotient −2009÷−49. Which estimate is most reasonable?

Mathematics
2 answers:
kobusy [5.1K]3 years ago
8 0

Answer:

41

Step-by-step explanation:

The answer is 41.

MariettaO [177]3 years ago
8 0

I would say I guess about around 41.

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(n 4 - 2n 3 - 3n 2 + 7n - 2) ÷ (n - 2)
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I believe it's 

- 1 - \frac{4}{n - 2}

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Micah deposited $4000 between two savings account. One account earns 4% simple interest each year. The other account earns 2% si
N76 [4]

Answer:

Step-by-step explanation:

$3000 * 0.04 = $120

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answer: $3000 was the originally deposited into the account that pays 4% interest.

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3 years ago
The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.
Scrat [10]

Just did a specific one of these; let's do the general case.


The point nearest the origin is (a,b).


The line from the origin through the point is


bx - ay = 0


The line we seek is perpendicular to this one. We swap the coefficients on x and y, negating one, to get the perpendicular family of lines. We set the constant by plugging in the point (a,b):


ax + by = a^2 + b^2


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That's standard form; let's plug in the numbers:


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5 0
3 years ago
Find the function value. tan495°
inysia [295]

Answer: -1

Step-by-step explanation:

You want to find an angle that is coterminal to 495. So, subtract 360 degrees until youre in the range of 0-360. I got 495 - 360 = 135°

Tangent is equal to \frac{sin(theta)}{cos(theta)}, we already solved theta which was 135°

This next part is hard to explain to someone who doesnt know their trig circle, idk if you do. The angle 135 is apart of the pi/4 gang. So we know this is going to be some variant of √2/2. Sine of quadrant 1 and 2 is gonna be positive:

sin135=\frac{\sqrt{2} }{2}

Now lets do cosine of 135°, which again is apart of the pi/4 gang because its divisible by 45°. Its in quadrant 2 so the cosine will be negative.

cos135=-\frac{\sqrt{2} }{2}

The final step is to divide them. They are both fractions so you should multiply by the reciprocal.

\frac{\sqrt{2} }{2} *-\frac{2}{\sqrt{2} } =-\frac{2\sqrt{2} }{2\sqrt{2} } =-1

7 0
4 years ago
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