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podryga [215]
3 years ago
15

What is 2,800 divided by 64

Mathematics
2 answers:
Sonja [21]3 years ago
5 0

Answer:

43.75

Step-by-step explanation:

jejejdjdjdudururjrjdjrir

xenn [34]3 years ago
3 0

Answer:

43.75

Step-by-step explanation:

Calculators NEVER lie

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T is the midpoint of KL. K has coordinates (2,−6), and T has coordinates (−4,2). Identify the coordinates of L.
kotykmax [81]

Answer:

L = (-10,10)

Step-by-step explanation:

Given

K = (2,-6)

T = (-4,2)

Required

Determine the coordinates of L

Since T is the midpoint of K and L, we make use of:

T_x = \frac{K_x + L_x}{2}

and

T_y = \frac{K_y + L_y}{2}

Solving for L_x

T_x = \frac{K_x + L_x}{2}

-4 = \frac{2 + L_x}{2}

Multiply through by 2

-8 = 2 + L_x

L_x = -8 - 2

L_x = -10

Solving for L_y

T_y = \frac{K_y + L_y}{2}

2 = \frac{-6+L_y}{2}

Multiply through by 2

4 = -6 + L_y

L_y = 4 + 6

L_y = 10

Hence: The coordinates of L is:

L = (-10,10)

6 0
3 years ago
5x+12=44 then value of 5x-12=?​
KATRIN_1 [288]

Answer:

If 5x+12=44 then value of 5x-12 is 20

Step-by-step explanation:

5x + 12 = 44

  • The first step, we have to find the value of x

5x + 12 = 44

5x = 44 - 12

5x = 32

x = 32/5

x = 6.4

  • After that, insert the value of x into 5x - 12

5x - 12 = ...

5 ( 32/5 ) - 12

= 32 - 12

= 20

3 0
3 years ago
A dart hits the circular dartboard shown below at a random point. Find the probability that the dart lands in the shaded circula
Feliz [49]
The probability of it landing in the shaded area is 4/10, or 2/5 simplified, or 40%. Hope this helps! <3
7 0
3 years ago
Read 2 more answers
Answer to this problem <br> 2³×(15-9)+7
Crazy boy [7]

Answer:

The answer is 55.

Step-by-step explanation:

hope this helps

2³×(15-9)+7

=8(15-9)+7

=120-72+7

=48+7

=55

6 0
3 years ago
Read 2 more answers
A line has an x-intercept of 4 and a y-intercept of -2. What is the equation of the line?
Evgesh-ka [11]

Answer:

y=x/2-2

Step-by-step explanation:

it's actually 1/2 times x is how your supposed to write it (like a fraction)

7 0
3 years ago
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