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denis-greek [22]
3 years ago
14

The circle P has a center at (0, 0) and a point on the circle at (0, 4). If it is dilated by a factor of 4, what is the distance

of the diameter for circle P’.
A. 32

B. 4

C. 8

D. 16
Mathematics
1 answer:
galina1969 [7]3 years ago
7 0

Answer:

A. 32

Step-by-step explanation:

If the center is (0, 0) and a point is (0, 4) then the distance from the center to that point is 4 units. That distance is the radius. If you are dilating by a factor of 4, multiply the radius by 4 and you get 16. The new radius is 16 and the diameter= radius*2.

16*2=32

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In the figure, AB∥CD. Find x and y.
velikii [3]

Answer:

y=131°

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Step-by-step explanation:

∠ ABD and ∠ BDC are supplementary.

The sum of the supplementary angles =180 °

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x and 37° are complementary, that  is, they add up to 90°

Thus, x=90-37=53°

Using this value in equation 1 we obtain:

y-4°+53° =180°

y= 180°-53°+4°

y=131°

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4 years ago
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Answer:

Step-by-step explanation:

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3 years ago
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ArbitrLikvidat [17]

Step-by-step explanation:

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4 years ago
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The following random sample was selected from a normal distribution: 4.5, 6.4, 2.3, 1.8, 5.3, then the 95% confidence interval t
kap26 [50]

Answer:

the 95% confidence interval to estimate the population mean is between  1.62 and 6.50

Step-by-step explanation:

given data

distribution = 4.5, 6.4, 2.3, 1.8, 5.3

so n = 5

confidence interval = 95%

to find out

the population mean is between

solution

first we calculate the mean i.e.

mean =  \frac{1}{n}\sum_{i=1}^{n}x(i)

mean =  4.5+ 6.4+ 2.3+ 1.8+ 5.3 / 5

mean = 4.06

now we calculate the standard deviation i.e.

standard deviation =   \sqrt{\frac{1}{n-1}\sum (x(i)-mean)^2}

standard deviation =   \sqrt{\frac{1}{5-1}\sum (x(i)-mean)^2}

standard deviation =   \sqrt{\frac{1}{5-1} (4.5-5)^2+(6.4-5)^2 +(2.3-5)^2+(1.8-5)^2+(5.3-5)^2}

standard deviation =   \sqrt{\frac{1}{4} (4.5-5)^2+(6.4-5)^2 +(2.3-5)^2+(1.8-5)^2+(5.3-5)^2}

standard deviation =  2.226544

so 95 % confidence interval is i.e. mean +/- t(5) * standard deviation/ \sqrt{n}

here t(5) will be 2.45

so

95 % confidence interval=  4.06 +/- 2.45 * 2.226 / \sqrt{5}

95 % confidence interval= 1.62 and 6.50

4 0
3 years ago
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Answer:

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Step-by-step explanation:

7 0
3 years ago
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